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System of Equations Calculator

Two equations, two unknowns — and the two ways it fails.

Work out System of Equations. Two equations, two unknowns — and the two ways it fails. Names the mistake before you make it.

Written and maintained by Mohit PatelLast checked August 4, 2026How we build these

In the form ax + by = c.

Solution

x = 1, y = 2

One solution — the point where the two lines cross

x1
y2
Determinant-5
OutcomeOne solution — the point where the two lines cross

Solved by Cramer's rule: each unknown is a ratio of two determinants. A non-zero determinant means the two lines cross at exactly one point. A zero determinant means they are parallel, and then there are two genuinely different outcomes. If the equations describe the same line, every point on it is a solution — infinitely many. If they describe distinct parallel lines, there is none at all. Reporting "no solution" for both would be wrong half the time, so this distinguishes them.

How the System of Equations Calculator works

Enter six coefficients in the form ax + by = c for both equations. Where the determinant is zero the page distinguishes parallel lines with no solution from identical lines with infinitely many, because those are genuinely different answers.

Also known as: simultaneous equations calculator · solve for x and y calculator · cramer's rule calculator · two equations two unknowns

Frequently asked questions

How do I solve two simultaneous equations?

By substitution, elimination, or Cramer's rule — each unknown as a ratio of two determinants, which is what this page uses. All three give the same answer when one exists.

What does a zero determinant mean?

The two lines are parallel. If they are the same line every point on it solves the system, giving infinitely many solutions. If they are distinct there is none at all. Reporting 'no solution' for both would be wrong half the time.

What is Cramer's rule?

Replace the coefficient column for the unknown you want with the constants, take that determinant, and divide by the determinant of the original coefficients. It generalises to any size, though elimination is faster beyond 3×3.

Why does my system have no solution?

Because the two equations describe parallel lines that never meet — the same slope with different intercepts. Geometrically there is no crossing point, and algebraically eliminating a variable leaves a contradiction like 0 = 3.

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The one-line version
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