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Voltage Drop Calculator

Over a long run, with the round trip counted.

Work out Voltage Drop. Over a long run, with the round trip counted. Says what it does not answer, as well as what it does.

Written and maintained by Mohit PatelLast checked August 4, 2026How we build these
A
ft

One way — the formula counts the return conductor.

V
%

3% on a branch circuit and 5% overall are the usual recommendations.

Voltage drop

6.58%

7.90 V lost · 112.1 V at the load

Voltage at the panel120 V
Voltage dropped7.902 V
Voltage at the load112.10 V
Drop as a percentage6.58%
Within the 3.0% limitno
Conductor area6,530 circular mils
Smallest size that meets 3.0%8 AWG (2.60%)

The run is counted twice — current goes out on one conductor and returns on the other — so a 100 foot run is 200 feet of conductor. Leaving out that factor of two is the commonest error in this calculation, and it halves the answer.

How the Voltage Drop Calculator works

Every conductor has resistance, so voltage arriving at a load is lower than voltage leaving the panel. Over a short run it is negligible; over a long one it is why the lights dim and the motor runs hot. The formula's easiest mistake is the factor of two on single phase — the current goes out on one conductor and back on the other, so the run counts twice.

Also known as: wire voltage drop calculator · cable voltage drop calculator · 3 percent voltage drop · long run voltage drop

The calculation itself

Every conductor has resistance, so some voltage is lost getting to the load. The standard formula uses circular mils:

Single phase: VD = 2 × K × I × L ÷ CM. Three phase: VD = √3 × K × I × L ÷ CM. K is 12.9 for copper and 21.2 for aluminium.

The 2 is the round trip. Current leaves on one conductor and returns on the other, so a 100-foot run is 200 feet of conductor. Omitting it halves the answer, and it is the commonest error in the calculation.

In practice

20 A over 100 feet of 12 AWG copper (6,530 circular mils) on a 120 V circuit:

VD = 2 × 12.9 × 20 × 100 ÷ 6,530 = 51,600 ÷ 6,530 = 7.90 V. That is 6.6% — well outside the usual 3% guidance, and the load sees 112 V rather than 120.

Going up to 8 AWG (16,510 circular mils) brings it to 3.13 V, or 2.6%, which clears the limit.

Three phase over the same run drops 6.84 V rather than 7.90, because √3 is smaller than 2 — one of several reasons long runs are often three phase.

Where the voltage goes

It is dissipated as heat in the conductor. So voltage drop is simultaneously a performance problem and an efficiency loss: the load underperforms and you pay for energy that warmed the cable.

Motors suffer most. Reduced voltage means reduced torque, which means the motor draws more current to do the same work, which increases the drop further. That feedback is why undersized motor runs fail rather than merely underperform.

Resistive loads simply do less — a heater at 6% low voltage delivers about 12% less heat, since power goes with the square of voltage.

Where the figure deceives

The 3% and 5% figures are recommendations in most codes rather than hard requirements, so a run can be technically compliant and still cause trouble.

The formula assumes DC-like behaviour and ignores reactance, which is fine for typical branch circuits and increasingly wrong for very large conductors and long AC runs.

It also assumes a constant load. Motor starting current is several times running current, so the drop at start is several times what this shows — which is why lights dim when the compressor kicks in.

Acting on it

Measure the actual cable route, not the straight-line distance. Runs follow walls and joists and are routinely half again as long as they look.

Check the drop at starting current for anything with a motor, not just at running current.

On a long run, upsizing at installation is cheap relative to pulling the cable again later.

Frequently asked questions

How do I calculate voltage drop?

For single phase: 2 × K × amps × length ÷ circular mils, with K being 12.9 for copper and 21.2 for aluminium. Three phase uses the square root of three in place of the two.

Why is the run counted twice?

Because the circuit is a loop. Current travels the length of the run to the load and the same length back, so the conductor length in the formula is twice the one-way distance.

What is an acceptable voltage drop?

Common practice is 3% on a branch circuit and 5% overall including the feeder. Those are recommendations in most codes rather than hard requirements, but equipment misbehaves beyond them.

Does voltage drop waste energy?

Yes — the dropped voltage is dissipated as heat in the conductor. It is both an efficiency loss and the reason an undersized run gets warm.

Does aluminium drop more than copper?

Yes, by roughly 64% for the same cross-section, which is why aluminium runs are sized larger. The constants in the formula are exactly that ratio: 21.2 against 12.9.

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