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Rydberg Equation Calculator

Hydrogen spectral lines from any pair of energy levels.

Work out Rydberg Equation. Hydrogen spectral lines from any pair of energy levels. Shows the working, not just the answer.

Written and maintained by Mohit PatelLast checked August 4, 2026How we build these

n₁ = 1 is the Lyman series, 2 is Balmer, 3 is Paschen.

1 for hydrogen. The formula only holds for one-electron species — H, He⁺, Li²⁺.

Emission wavelength

656.47 nm

Balmer (visible)

Wavelength656.47 nm
Frequency4.567e+14 Hz
Photon energy1.8887 eV
SeriesBalmer (visible)
DirectionEmission — electron falls

Only the Balmer series lands in visible light, which is why hydrogen's famous lines — red H-alpha at 656.5 nm, blue-green at 486.3 nm — all end on n = 2. These are vacuum wavelengths; books quoting 656.28 nm are giving the value in air. Lyman transitions are ultraviolet and Paschen onwards are infrared. Energy scales as Z², so He⁺ emits at a quarter of hydrogen's wavelength for the same pair of levels. Beyond one electron the equation fails, because electron–electron repulsion is not in it.

How the Rydberg Equation Calculator works

Pick two energy levels and this gives the wavelength, frequency and photon energy of the transition between them, plus which named series it belongs to. Hydrogen uses its reduced-mass-corrected Rydberg constant rather than R∞, so the lines match the values printed in textbooks. Set Z above 1 for hydrogen-like ions such as He⁺ and Li²⁺, where the energies scale as Z².

Also known as: hydrogen spectrum calculator · balmer series calculator · lyman series calculator · hydrogen emission wavelength

Frequently asked questions

What is the Rydberg equation?

1/λ = R·Z²·(1/n₁² − 1/n₂²). For hydrogen R is 1.09678 × 10⁷ m⁻¹ — the reduced-mass-corrected value, not R∞ — and the result is the wavelength emitted or absorbed as an electron moves between levels n₁ and n₂.

Why is only the Balmer series visible?

Because of where the energies land. Transitions ending on n = 2 happen to fall between 380 and 660 nm — H-alpha at 656 nm is the red line that gives nebulae their colour. Lyman transitions ending on n = 1 are ultraviolet, and Paschen onwards are infrared.

Does the Rydberg equation work for other elements?

Only for one-electron species: H, He⁺, Li²⁺, Be³⁺. Once there are two electrons they repel each other, and that repulsion is not in the equation. Multi-electron spectra need quantum mechanical calculation.

What is the series limit?

The wavelength when n₂ goes to infinity — the electron is removed entirely. For the Lyman series that is 91.18 nm, corresponding to hydrogen's 13.6 eV ionisation energy.

Why does my book say H-alpha is 656.28 nm?

Because that is the wavelength in air. These are vacuum wavelengths, and air's refractive index shortens visible light by about 0.03%. Vacuum 656.47 nm and air 656.28 nm are the same line.

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